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Miro Art Studio @ Beauty World Centre

He attended art class at Miro Art Studio @ Beauty World Centre from October 12th, 2019 to October 3rd, 2020. In average, S$35 for each art class session. Some of his drawings at his aunt house. :) Drawing in action. :) Below are all the drawings completed at Miro Art, total 35x artworks.  THE END

Primary 5 Maths: Properties of 4-sided Figures

The common 4-sided figures learnt in Primary 5 are parallelogram, rhombus, trapezium and isosceles trapezium . Master the properties/characteristics of these 4-sided figures! (1) Parallelogram AB parallel with DC.  That's why we can say adjacent angles, angle a + angle d = 180 degree , similarly angle b + angle c = 180 degree . DA parallel with CB.  So adjacent angles, angle d + angle c = 180 degre e, similarly angle a + angle b = 180 degree . In addition, angle b = angle d (opposite angles), angle c = angle a . (2) Rhombus AB parallel with DC and DA parallel with CB.  That's why rhombus has all the same properties as parallelogram above.  In rhombus, all sides are equal , hence angle d1 = angle d2 = half of the angle d . (3) Trapezium  AB parallel with DC. Therefore, adjacent angles, angle a + angle d = 180 degree , similarly angle b + angle c = 180 degree . NOTE: (very important !) adjacent angle d + angle c is NOT EQUAL to 180 degree adjacent angle a +...

5x PSLE Math questions: 2009, 2012, 2013, 2017, 2020

  Here are the questions posted at The Straits Times.         The trick here is the blocks of Ken. It contains the extra “12” if you would want to compare with Jim ratio from sweets to chocolates. It is because the ratio of sweets at Jim and Ken are both “1”. Hence, to find the 3 units of Jim, you need to include the “12” in the 4 blocks, that gives you a unit of 22. To find Ken’s sweets, do remember to add back the “12” as the unit of 22 mentioned above is for Jim. a) Remember the bakery is exactly half-way between the two houses. Hong cycled 120m more and Jeya cycled 120m less too! In total, Hong cycled 120m x 2 = 240m more than Jeya. b) Hong cycled 15 m/minute faster than Jeya. 240m/ 15 = 16 minutes. You can imagine in this way. In order to cycle 240m more than Jeya, Hong needed to cycle 16 minutes because every minute, he was 15m more than Jeya.    Hong and Jeya timings were the same, both travel time were 16 minutes.   Jeya speed was 7...